
Find
i) What is the perpendicular distance of A (165, 250) from x axis. [1 Marks]
ii) In which quadrant the abscissa of a point is negative. [1 Marks]
iii) What is the sum of abscissa of A and B. [2 Marks]
Doubt Question by Purvi
Solution :
(i) 250 units.
(ii) II and III Quadrant
Solution :
(i) 250 units.
(ii) II and III Quadrant
(iii)
A(165, 250)
A(165, 250)
B(300, 250)
Sum of abscissa of A and B
=165+300
= 465
=165+300
= 465