Doubt by Aditi
Solution :
27-125a³-135a+225a²
= (3)³-(5a)³-3(3)²(5a)+3(3)(5a)²
[∵ x³-y³-3x²y+3xy²=(x-y)³]
[∵ x³-y³-3x²y+3xy²=(x-y)³]
Here x=3 and y=5a
= (3-5a)³
= (3-5a)(3-5a)(3-5a)
Hence, the required factors of the given polynomials are (3-5a), (3-5a) and (3-5a).