Doubt by Aditi
Solution :
In figure
∠AOB+∠BOC+∠COA=360° (Complete Angle)
80°+∠BOC+110°=360°
∠BOC+190°=360°
∠BOC = 360°-190°
∠BOC = 170°
80°+∠BOC+110°=360°
∠BOC+190°=360°
∠BOC = 360°-190°
∠BOC = 170°
Also,
∠BOC=2∠BAC [Angle subtended by an arc at the centre is twice the angle subtended by it at any point on the remaining part of the circle]
∠BOC=2∠BAC [Angle subtended by an arc at the centre is twice the angle subtended by it at any point on the remaining part of the circle]
170°=2∠BAC
∠BAC = 170°/2
∠BAC = 85°
∠BAC = 170°/2
∠BAC = 85°
Hence, ∠BAC is 85°.