Question : Evaluate (a2b-b2a)2 using suitable identities.
Doubt by Aditi
Solution :
Solution :
[a2b-b2a]2
= [ab(a-b)]2
=a2b2(a-b)2
=a2b2(a2+b2-2ab)
= [ab(a-b)]2
=a2b2(a-b)2
=a2b2(a2+b2-2ab)
[Using Identity : (x-y)2=x2+y2-2xy]
=a2b2(a2+b2-2ab)
= a4b2+a2b4-2a3b3
= a4b2+a2b4-2a3b3