6/(3√2-2√3) = 3√2-a√3
Doubt by Saksham
Solution :
6/(3√2-2√3) = 3√2-a√3
[6/(3√2-2√3)][3√2+2√3/(3√2+2√3)] = 3√2-a√3
6(3√2+2√3)/[(3√2-2√3)(3√2+2√3)] = 3√2-a√3
6(3√2+2√3)/[(3√2)²-(2√3)²] = 3√2-a√3
6(3√2+2√3)/[18-12] = 3√2-a√3
6(3√2+2√3)/[6] = 3√2-a√3
3√2+2√3 = 3√2-a√3
3√2-(-2)√3 = 3√2-a√3
∴ a=-2