The definition of temperature says that it is a measure of the hotness and coldness of a body. The two main units we often use to measure temperature are degree Celsius and degree Fahrenheit.
The linear equation that converts Fahrenheit (F) to Celsius (C) is given by
°C×1.8=°F-32
Based on the above information, answer the following questions :
(i) Convert the normal body temperature in degree Celsius.
(ii) If the room temperature on a day is 35°C, then what will be its value in Fahrenheit scale ?
(iii) (A) Convert the freezing point and boiling point of water in Fahrenheit scale.
OR
(B) What is the numerical value of the temperature which is same in both the scales ?
Doubt by Parth
Solution :
(i) Normal body temperature in Fahrenheit (F) = 98.6 °F
°C×1.8=°F-32
=°C×1.8=98.6-32
=°C×1.8=66.6
=°C=66.6/1.8
°C=666/18
°C=222/6
°C=37
°C×1.8=°F-32
=°C×1.8=98.6-32
=°C×1.8=66.6
=°C=66.6/1.8
°C=666/18
°C=222/6
°C=37
Normal body temperature in degree Celsius is 37°C
(ii) Room Temperature = 35°C
°C×1.8=°F-32
35×1.8=°F-32
63=°F-32
63+32=°F
95=°F
°F=95
35×1.8=°F-32
63=°F-32
63+32=°F
95=°F
°F=95
Hence, room temperature in Fahrenheit scale will be 95°F.
(iii) (A)
Freezing Point of water = 0°C
Boiling Point of water = 100 °C
°C×1.8=°F-32
°F-32=°C×1.8
°F=[°C×1.8]+32
°F=[0×1.8]+32
°F=0+32
°F=32
°F=[100×1.8]+32
°F=180+32
°F=212
Hence, freezing point and boiling point is 32°F and 212°F respectively.
Freezing Point of water = 0°C
Boiling Point of water = 100 °C
°C×1.8=°F-32
°F-32=°C×1.8
°F=[°C×1.8]+32
°F=[0×1.8]+32
°F=0+32
°F=32
°F=[100×1.8]+32
°F=180+32
°F=212
Hence, freezing point and boiling point is 32°F and 212°F respectively.
OR
(B) Let °C=°F=a
°C×1.8=°F-32
a×1.8=a-32
1.8a-a=-32
0.8a=-32
a=-32/0.8
a=-320/8
a=-40
°C×1.8=°F-32
a×1.8=a-32
1.8a-a=-32
0.8a=-32
a=-32/0.8
a=-320/8
a=-40
Hence, the numerical value of the temperature which is same in both the scale is -40°.