If an angle is 30° more than one half of its complementary . . .

Question : If an angle is 30° more than one half of its complementary , find the measure of the angle.

Doubt by Bhavya

Solution : 

Let the measure of the required angle be x°

and the measure of its complementary angle be (90-x)°

ATQ
x°=30°+½(90-x)°

x°-30 = ½(90-x)°

2(x°-30) = (90-x)°
2x°-60°=90-x°
2x°-x°=90+60

3x°=150°

x°=150°/3
x°=50°

Hence, the required angle is 50°