Two coins are tossed simultaneously for 360 . . .

Question : Two coins are tossed simultaneously for 360 times. The number of times '2 Tails' appeared was three times 'No Tail' appeared and number of times '1 tail' appeared is double the number of times 'No Tail' appeared. find the probability of getting 'Two tails'.

Doubt by Saksham

Solution : 

When two coins are tossed then possible outcomes are
HH = Two Heads = No Tail 
HT = Head on first coin and Tail on the second coin.

TH = Tail on first coin and Head on the second coin.
TT = Two tails = Zero Tails  = No Tails

Total No. of times the two coins are tossed = 360.

Let the number of times No Tails appeared (HH)= x

ATQ

No. of times 'Two Tails' appeared (TT)
= 3× No. of times of no tails appeared. (HH)
=3x

Also, 
No. of times 'One Tail' appeared [(HT), (TH)] 
= 2× No. of times of no tails appeared. (HH)

= 2x

Now, 
n(HH)+n[(HT),(TH)]+n(TT) = 360
x+2x+3x = 360
6x=360
x=360/6
x=60

= 0.5

Hence, the probability of getting 'Two Heads' is 0.5.